J & K CET Medical J & K - CET Medical Solved Paper-2002

  • question_answer
    The average power dissipated in a pure inductor of inductance L is :

    A) \[\frac{L{{I}^{2}}}{2}\]                                   

    B) \[L{{I}^{2}}\]

    C) \[\frac{L{{I}^{2}}}{4}\]                                   

    D)  zero

    Correct Answer: D

    Solution :

                    The rate of dissipation of energy in an electrical circuit is called power. It is given by \[P={{i}_{rms}}\times {{E}_{rms}}\times \cos \phi \] In a purely .inductive circuit resistance is zero, then phase between current and voltage is \[90{}^\circ \]hence, average power is \[{{P}_{avg}}={{E}_{rms}}\times {{i}_{rms}}\times \cos {{90}^{o}}=0\] Hence, no energy dissipation in the circuit.


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