A) 1764 J
B) 1600 J
C) 160 J
D) 176 J
Correct Answer: A
Solution :
Total heat given to u, mole of nitrogen is \[Q=\mu {{C}_{p}}\Delta T=0.2\times 7\times 300=420\text{ }cal\] This heat is equivalent to\[420\times 4.2=1764\text{ }J\]
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