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J & K CET Medical J & K - CET Medical Solved Paper-2002

  • question_answer
    A spring having a spring constant k is loaded with a mass m. The spring is cut into two parts and one of them is loaded again with same mass. The new constant is :

    A)  \[\frac{k}{2}\]                                  

    B)  k

    C)  2k                                         

    D)  k2

    Correct Answer: C

    Solution :

                    When spring constant is k and I is extension produced in spring when force F is applied, then \[F=-kl=mg\] When spring is cut into two parts, its length is halved \[\left( \frac{l}{2} \right)\] \[\therefore \]  \[k=\frac{mg}{l/2}=2k\]


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