J & K CET Medical J & K - CET Medical Solved Paper-2002

  • question_answer
    The empty space between the plates capacitor is filled by a liquid of constant K. The capacitance of capacitor:

    A)  increases by a factor \[{{K}^{2}}\]

    B)  increases by a factor K

    C)  decreases by a-factor \[{{K}^{2}}\]

    D)  decreases by a factor K

    Correct Answer: B

    Solution :

                    The capacity of a parallel plate capacitor of plate area A, separated by distance d is \[C=\frac{K{{\varepsilon }_{0}}A}{d}\]                                    ?. (i) where K is dielectric constant. Also, capacity in air, K = 1 \[C=\frac{{{\varepsilon }_{0}}A}{d}\]                                      ...(ii) From Eqs. (i) and (ii), we get \[C\text{ }=KC\] Hence, capacity increases by a factor K.


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