A) \[ClC{{H}_{2}}COOH>C{{H}_{3}}COOH>HCOOH>\]\[{{C}_{6}}{{H}_{5}}OH\]
B) \[ClC{{H}_{2}}COOH>HCOOH>C{{H}_{3}}COOH>\]\[{{C}_{6}}{{H}_{5}}OH\]
C) \[ClC{{H}_{2}}COOH>HCOOH>{{C}_{6}}{{H}_{5}}OH>\]\[C{{H}_{3}}COOH\]
D) \[ClC{{H}_{2}}COOH>C{{H}_{3}}COOH>{{C}_{6}}{{H}_{5}}OH>\]\[HCOOH\]
Correct Answer: B
Solution :
The acidic strength of acid increases by\[-I\]effect of chlorine atom and decreases by\[+I\] effect of methyl group. Further, phenol is the less acidic than carboxylic acid because phenoxide ion is less stabilized by resonance than carboxylate ion. Hence, the order of acidic strength is as: \[ClC{{H}_{2}}COOH>HCOOH>C{{H}_{3}}COOH>{{C}_{6}}{{H}_{5}}OH\]
You need to login to perform this action.
You will be redirected in
3 sec
