A) In\[N_{2}^{+},\]the\[N-N\]bond weakens
B) In\[O_{2}^{+},O-O\]bond order increases
C) In\[O_{2}^{+},\]pararnagnetism decreases
D) \[N_{2}^{+}\] becomes diamagnetic
Correct Answer: D
Solution :
\[{{N}_{2}}:KK\] \[{{(\sigma 2s)}^{2}}{{({{\sigma }^{*}}2s)}^{2}}{{(\pi 2{{p}_{x}})}^{2}}{{(\pi 2{{p}_{y}})}^{2}}{{(\sigma 2{{p}_{z}})}^{2}}\] Bond order \[=\frac{{{N}_{b}}-{{N}_{a}}}{2}=\frac{8-2}{2}=3\] It is diamagnetic in nature. \[N_{2}^{+}:KK(\sigma 2{{s}^{2}}){{({{\sigma }^{*}}2s)}^{2}}{{(\pi 2{{p}_{x}})}^{2}}{{(\pi 2{{p}_{y}})}^{2}}{{(\sigma 2{{p}_{z}})}^{1}}\] Bond order\[=\frac{7-2}{2}=2.5\] It is paramagnetic in nature.
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