A) \[C{{H}_{2}}=C{{H}_{2}}\]
B)
C)
D)
Correct Answer: D
Solution :
According to Markownikoffs rule the addition of a reagent (HX) to an unsymmetrical alkene takes place in such a way that the negative part of the reagent will be attached to the carbon atom which contains lesser number of \[H\]atom. \[\underset{2-methylpropene}{\mathop{C{{H}_{3}}-\underset{\begin{smallmatrix} | \\ C{{H}_{3}} \end{smallmatrix}}{\mathop{C}}\,=C{{H}_{2}}}}\,+HBr\xrightarrow{{}}C{{H}_{3}}-\underset{\begin{smallmatrix} | \\ C{{H}_{3}} \end{smallmatrix}}{\overset{\begin{smallmatrix} Br \\ | \end{smallmatrix}}{\mathop{C}}}\,-C{{H}_{3}}\]
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