A) \[{{H}_{3}}C-C\equiv CH\]
B) \[{{H}_{3}}C-C\equiv C-C{{H}_{3}}\]
C) \[{{H}_{2}}C=C{{H}_{2}}\]
D) \[{{H}_{3}}C-C{{H}_{3}}\]
Correct Answer: A
Solution :
The\[H\]atoms of terminal alkyne (i.e., \[{{H}_{3}}-C\equiv CH)\]is weakly acidic. \[CH\equiv CH+NaN{{H}_{2}}\xrightarrow{liq.\text{ }N{{H}_{3}}}CH\equiv CNa+N{{H}_{3}}\]
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