A) 1-butanol
B) 2-butanol
C) 3-pentanol
D) 4-heptanol
Correct Answer: B
Solution :
A carbon atom which is attached by four different group is called an asymmetric carbon atom or chiral centre and a compound which contain a chiral carbon atom is called optically active compound. \[\underset{butan-2-ol\text{ }or\text{ }2-butanol}{\mathop{C{{H}_{3}}-C{{H}_{2}}-\underset{\begin{smallmatrix} | \\ OH \end{smallmatrix}}{\overset{\begin{smallmatrix} H \\ | \end{smallmatrix}}{\mathop{{{C}^{*}}}}}\,-C{{H}_{3}}}}\,\] Hence, 2-butanol can exist in optically active form.
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