A) isobutene
B) isobutylene
C) sodium-t-butoxide
D) t-butylmethylether
Correct Answer: B
Solution :
\[\underset{t-butyl-bromide}{\mathop{C{{H}_{3}}-\underset{\begin{smallmatrix} | \\ C{{H}_{3}} \end{smallmatrix}}{\overset{\begin{smallmatrix} C{{H}_{3}} \\ | \end{smallmatrix}}{\mathop{C}}}\,-Br}}\,+\underset{\begin{smallmatrix} sodium \\ methoxide \end{smallmatrix}}{\mathop{C{{H}_{3}}ONa}}\,\to \underset{\begin{smallmatrix} 2-methyl\text{ }propene \\ \,\,\,\,\,\,(isobutylene) \end{smallmatrix}}{\mathop{C{{H}_{3}}-\overset{\begin{smallmatrix} C{{H}_{3}} \\ | \end{smallmatrix}}{\mathop{C}}\,=C{{H}_{2}}}}\,\]\[+\underset{Methanol}{\mathop{C{{H}_{3}}OH}}\,+NaBr\]
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