A) 1.36, 1.40, 1.71
B) 1.36, 1.71, 1.40
C) 1.71, 1.40, 1.36
D) 1.71, 1.36, 1.40
Correct Answer: C
Solution :
The size of isoelectronic species decreases with increasing nuclear charge. Hence, the order of ionic radii of\[N_{3}^{-},{{O}^{2-}}\]and\[{{F}^{-}}\]is as: \[\begin{align} & N_{3}^{-}\,\,\,\,\,>\,\,{{O}^{2-}}\,\,\,\,>\,\,\,{{F}^{-}} \\ & 1.71~~\,\,\,~~1.40~~~~~~1.36 \\ \end{align}\]You need to login to perform this action.
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