A) 200
B) 100
C) 50
D) 400
Correct Answer: B
Solution :
The average power consumed in an AC circuit is given by \[P=\frac{{{V}_{0}}{{I}_{0}}}{2}\cos \phi \] where\[\phi \]is phase angle and\[{{V}_{0}}\]and\[{{I}_{0}}\]the peak value of voltage and current. Given, \[{{V}_{0}}=200\,V,{{I}_{0}}=2A,\phi =\frac{\pi }{3}\] \[P=\frac{200\times 2}{2}\cos \frac{\pi }{3}\] \[=\frac{200\times 2}{2}\times \frac{1}{2}=100\,W\]
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