A) \[[M{{L}^{-2}}{{T}^{-3}}]\]
B) \[[M{{L}^{2}}{{V}^{-1}}]\]
C) \[[ML{{T}^{-2}}]\]
D) \[[M{{L}^{-2}}{{T}^{-1}}]\]
Correct Answer: B
Solution :
From Plancks law, energy of a photon of frequency v is given by \[E=hv\]where h is Plancks constant. \[\therefore \] Dimensions of \[h=\frac{Dimensions\text{ }of\text{ }E}{Dimensions\text{ }of\text{ }v}\] Dimensions of\[h=\frac{[M{{L}^{2}}{{T}^{-2}}]}{[{{T}^{-1}}]}\] \[=[M{{L}^{2}}{{T}^{-1}}]\]
You need to login to perform this action.
You will be redirected in
3 sec
