(I) \[n=4,l=1\] |
(II) \[n=4,l=0\] |
(III) \[n=3,l=2\] |
(IV) \[n=2,l=1\] |
A) (IV) < (II) < (III) < (I)
B) (II) < (IV) < (I) < (I)
C) (I) < (III) < (II) < (IY)
D) (III) < (I) < (IV) < CH)
Correct Answer: A
Solution :
(I) For\[n=4,l=1;4p\] (II) For\[n=4,l=0;4s\] (III) For\[n=3,l=2;3d\] (IV) For\[n=2,l=1;2p\] The order of increasing energy is as: \[2p<45\text{ }<3d<4p\] i.e., (IV) < (II) < (III) < (I)You need to login to perform this action.
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