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J & K CET Medical J & K - CET Medical Solved Paper-2003

  • question_answer
    A tuning fork of frequency 500 cycles/s is sounded on a resonance tube. The first and second resonance is obtained at 17 cm and 52 cm. The velocity of sound in m/s is :

    A)  175                                       

    B)  350

    C)  525                                       

    D)  700

    Correct Answer: B

    Solution :

                    Resonance tube is a closed organ pipe is having an air column of variable length. If the frequency of fork n, then speed of sound is given by \[v=2n({{l}_{2}}-{{l}_{1}})\] where\[{{l}_{1}}\]and\[{{l}_{2}}\]are length of air column. Given,\[n=500\]cycles/s,                 \[{{l}_{2}}=52\,cm=52\times {{10}^{-2}}m\]                 \[{{l}_{1}}=17\,cm=17\times {{10}^{-2}}m\] \[\therefore \]  \[v=2\times 500(0.52-17)\times {{10}^{-2}}\] \[\Rightarrow \]               \[v=350\text{ }m/s\]


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