A) \[\frac{V}{2r}\]
B) \[\frac{V}{3r}\]
C) \[\frac{V}{4r}\]
D) \[\frac{V}{6r}\]
Correct Answer: D
Solution :
The potential at a distance r, due to charge q is \[V=\frac{1}{4\pi {{\varepsilon }_{0}}}.\frac{q}{r}\]You need to login to perform this action.
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