A) 1 mm/s
B) 2 mm/s
C) 0.5 mm/s
D) 0.36 mm/s
Correct Answer: D
Solution :
Drift velocity is the average velocity that a particle such as an electron, attains due to an electric field. It is given by \[{{v}_{d}}=\frac{I}{nqA}\] where\[I\]is current, n the number of electrons, A the area, q the charge. Given, \[\frac{I}{A}=\frac{480A}{c{{m}^{2}}},q=1.6\times {{10}^{-19}}C\] \[n=\frac{6\times {{10}^{23}}\times 9}{64}\] \[\therefore \] \[{{v}_{d}}=480\times \frac{64}{6\times {{10}^{23}}\times 9\times 1.6\times {{10}^{-19}}}\] \[\Rightarrow \] \[{{v}_{d}}=\frac{480\times 64}{6\times 9\times 1.6\times 10000}cm/s\] \[\Rightarrow \] \[{{v}_{d}}=\frac{32}{900}cm/s\] \[=\frac{32\times 10}{900}mm/s\] \[=0.36\,mm/s\] \[\Rightarrow \] \[{{v}_{d}}=0.36\,mm/s\]
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