A) zero
B) \[\frac{\pi }{4}\]
C) \[\pi \]
D) \[\frac{\pi }{2}\]
Correct Answer: D
Solution :
Magnetic field exerts force\[(\overrightarrow{F})\]on moving charge (q) is given by \[\overrightarrow{\mathbf{F}}=q\overrightarrow{\mathbf{v}}\times \overrightarrow{\mathbf{B}}=q\overrightarrow{\mathbf{v}}\overrightarrow{\mathbf{B}}\sin \theta \] where\[\overrightarrow{\mathbf{v}}\]is velocity,\[\overrightarrow{\mathbf{B}}\]the magnetic field, and\[\theta \]the angle between the two. F is maximum when\[\sin \theta \]is maximum. Therefore, \[\theta =\frac{\pi }{2},\]\[\sin \frac{\pi }{2}=1\]
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