A) \[\frac{H}{2}\]
B) \[\frac{2H}{\sqrt{3}}\]
C) \[H\sqrt{2}\]
D) \[H\sqrt{3}\]
Correct Answer: B
Solution :
Angle of dip is defined as the angle at a particular point on the earths surface between the direction of the earths magnetic field and horizontal. Therefore, \[H=B\text{ }cos\theta \] where B is total field intensity, H the horizontal component of earths magnetic field and\[\theta \]the dip angle. Given, \[\theta ={{30}^{o}},\] \[\because \]\[\cos {{30}^{o}}=\frac{\sqrt{3}}{2}\] \[\therefore \] \[B=\frac{H}{\cos {{30}^{o}}}=\frac{2H}{\sqrt{3}}\]
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