2. Solved Papers
  3. J & K CET Medical

J & K CET Medical J & K - CET Medical Solved Paper-2003

  • question_answer
    A tuning fork of frequency 480 Hz produces 10 beats/s, when sounded With a sonometer string. A slight increase in tension in the sonometer string produces fewer beats/s than before. What was the frequency of sonometer string?

    A)  470 Hz                                 

    B)  490 Hz

    C)  480 Hz                                 

    D)  460 Hz

    Correct Answer: A

    Solution :

                    Beats are produced when two waves whose frequencies are only slightly different interfere with each other. \[{{f}_{b}}=|{{f}_{1}}-{{f}_{2}}|\] \[\therefore \]  \[10=480-f\]                                 ...(i)  \[10=f-480\]                             ...(ii) Since, beats decrease, hence \[f=480-10=470\]


You need to login to perform this action.
You will be redirected in 3 sec spinner