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J & K CET Medical J & K - CET Medical Solved Paper-2003

  • question_answer
    The electrons identified by quantum numbers:  
     (I) \[n=4,l=1\] 
     (II) \[n=4,l=0\] 
     (III) \[n=3,l=2\]   
     (IV) \[n=2,l=1\] 
    can be placed in order of increasing energy from the lowest to highest as:

    A)  (IV) < (II) < (III) < (I)

    B)  (II) < (IV) < (I) < (I)

    C)  (I) < (III) < (II) < (IY)

    D)  (III) < (I) < (IV) < CH)

    Correct Answer: A

    Solution :

                    (I) For\[n=4,l=1;4p\] (II) For\[n=4,l=0;4s\] (III) For\[n=3,l=2;3d\] (IV) For\[n=2,l=1;2p\] The order of increasing energy is as: \[2p<45\text{ }<3d<4p\] i.e., (IV) < (II) < (III) < (I)


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