A) \[\frac{1}{2}g\]
B) \[\frac{1}{5}g\]
C) \[\frac{1}{4}g\]
D) \[\frac{1}{32}g\]
Correct Answer: D
Solution :
T = 800 days \[{{t}_{1/2}}=160\text{ }days\] \[n=\frac{T}{{{t}_{1/2}}}=\frac{800}{160}=5\] \[\frac{N}{{{N}_{0}}}={{\left( \frac{1}{2} \right)}^{n}}\] \[N={{N}_{0}}{{\left( \frac{1}{2} \right)}^{n}}=1{{\left( \frac{1}{2} \right)}^{5}}\] \[N=\frac{1}{32}g\]
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