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J & K CET Medical J & K - CET Medical Solved Paper-2003

  • question_answer
    In the reaction\[2A+B\xrightarrow[{}]{{}}{{A}_{2}}B,\]if the concentration of A is doubled and that of B is halved, then the rate of reaction will:

    A)  increase by 4 times

    B)  decrease by 2 times

    C)  increase by 2 times

    D)  remains the same

    Correct Answer: C

    Solution :

                    For the reaction: \[2A+B\xrightarrow[{}]{{}}{{A}_{2}}B\] \[r=k{{[A]}^{2}}[B]\] If concentration of A is doubled and B is halved, then \[r={{[2A]}^{2}}\left[ \frac{B}{2} \right]\]                 \[=2k{{[A]}^{2}}[B]\]                 \[r=2r\] Hence, if the concentration of [A] is doubled and B is halved, then rate of reaction increases by 2 times.


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