A) 91.3%
B) 87%
C) 100%
D) 74%
Correct Answer: B
Solution :
\[Ba{{(N{{O}_{3}})}_{2}}B{{a}^{2+}}+2NO_{3}^{-}\] \[\begin{matrix} At\,t=0 & \,\,\,\,\,\,0.1\,M & \,\,\,\,\,\,\,\,0 & \,\,\,\,\,\,\,\,\,\,\,0 \\ At\,eqm. & \,\,\,\,\,\,\,\,\,\,\,(0.1-x)M & \,\,\,\,\,\,\,\,\,\,\,x\,M & \,\,\,\,\,\,\,\,\,2x\,M \\ \end{matrix}\] \[i=\frac{(0.1-x)+x+2x}{0.1}\] \[2.74=\frac{0.1+2x}{0.1}\] \[2.74=\frac{0.1+2x}{0.1}\] \[0.1+2x=0.274\] \[2x=0.274-0.1=0.174\] \[x=\frac{0.174}{2}=0.087\] \[\therefore \]degree of dissociation\[=\frac{0.087}{0.1}\times 100=87%\]
You need to login to perform this action.
You will be redirected in
3 sec
