A) 4300\[\overset{0}{\mathop{A}}\,\]
B) 9600\[\overset{0}{\mathop{A}}\,\]
C) 2400\[\overset{0}{\mathop{A}}\,\]
D) 19200\[\overset{0}{\mathop{A}}\,\]
Correct Answer: B
Solution :
We ins displacement law states that there is an inverse relationship between the wavelength\[({{\lambda }_{m}})\]of the peak of the emission of a black body and its temperature (T). \[\therefore \] \[{{\lambda }_{m}}=\frac{b}{T}\] (b = constant) \[\therefore \] \[\frac{{{\lambda }_{1}}}{{{\lambda }_{2}}}=\frac{{{T}_{2}}}{{{T}_{1}}}\] \[\Rightarrow \] \[{{\lambda }_{2}}=\frac{{{\lambda }_{1}}{{T}_{1}}}{{{T}_{2}}}\] Given, \[{{\lambda }_{1}}=4800\text{ }{\AA},\text{ }{{T}_{1}}=6000\text{ }K,\] \[{{T}_{2}}=3000\text{ }K.\] \[\therefore \] \[{{\lambda }_{2}}=\frac{4800\times 6000}{3000}=9600{\AA}\]You need to login to perform this action.
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