A) \[12\times {{10}^{-1}}Nm\]
B) \[12\times {{10}^{-3}}Nm\]
C) \[24\times {{10}^{-1}}Nm\]
D) \[24\times {{10}^{-3}}Nm\]
Correct Answer: B
Solution :
Torque\[(\tau )\]on a dipole in an electric field (E) is given by \[\tau =pE\sin \theta \] where p is electric dipole moment. \[\therefore \] \[\tau =(q\times l)E\sin \theta \] Torque is maximum, when\[\theta =90{}^\circ ,\] \[\sin 90{}^\circ =1\] \[\therefore \] \[\tau =qlE\] \[=2\times {{10}^{-6}}\times \frac{3}{100}\times 2\times {{10}^{5}}\] \[\tau =12\times {{10}^{-3}}Nm\]You need to login to perform this action.
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