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J & K CET Medical J & K - CET Medical Solved Paper-2004

  • question_answer
    The decreasing order of bond angle is:

    A)  \[N{{O}_{2}}>NO_{2}^{+}>NO_{2}^{-}\]

    B) \[NO_{2}^{-}>N{{O}_{2}}>NO_{2}^{+}\]

    C)  \[NO_{2}^{+}>N{{O}_{2}}>NO_{2}^{-}\]

    D)  \[NO_{2}^{+}>NO_{2}^{-}>N{{O}_{2}}\]

    Correct Answer: C

    Solution :

                    The decreasing order of bond angle is as: Species:               \[NO_{2}^{+}\,\,\,>\,\,\,N{{O}_{2}}\,\,\,\,>\,\,NO_{2}^{-}\] Bond angle:        \[180{}^\circ ~~~\,\,\,\,\,135{}^\circ ~~\,\,\,\,~115{}^\circ \]


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