A) \[N<Be<B\]
B) \[{{F}^{-}}<{{O}^{2-}}<{{N}^{3-}}\]
C) \[Na<Li<K\]
D) \[F{{e}^{3+}}<F{{e}^{2+}}<F{{e}^{4+}}\]
Correct Answer: B
Solution :
\[{{F}^{-}},\text{ }{{O}^{2-}}\]and\[{{N}^{3-}}\]are isoelectronic species. They have 8 electrons. The size of isoelectronic species decreases with increasing nuclear charge. Hence, the order of radii is: \[{{F}^{-}}<{{O}^{2-}}<{{N}^{3-}}\]
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