A) \[43kg-{{m}^{2}}\]
B) \[34kg-{{m}^{2}}\]
C) \[27\text{ }kg-{{m}^{2}}\]
D) \[72kg-{{m}^{2}}\]
Correct Answer: A
Solution :
Moment of inertia of the whole system about the axis of rotation will be equal to the sum of the moments of inertia of all the particles. \[I={{I}_{1}}+{{I}_{2}}+{{I}_{3}}+{{I}_{4}}\] \[\therefore \] \[I={{m}_{1}}r_{1}^{2}+{{m}_{2}}r_{2}^{2}+{{m}_{3}}r_{3}^{2}+{{m}_{4}}r_{4}^{2}\] \[I=(1\times 0)+(2\times 0)+(3\times {{3}^{2}})+4{{(-2)}^{2}}\] \[I=0+0+27+16=43\text{ }kg-{{m}^{2}}\]You need to login to perform this action.
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