A) 3 cm
B) 0.3 cm
C) 3 mm
D) 3 m
Correct Answer: A
Solution :
For no leakage, \[h\rho g=\frac{2T}{R}\] \[\Rightarrow \] \[T=\frac{Rh\rho g}{2}\] \[\Rightarrow \] \[h=\frac{2T}{R\rho g}\] Given, \[T=75\times {{10}^{-3}}N/m,\text{ }g=10\text{ }m/{{s}^{2}},\] \[R=0.5\times {{10}^{-3}}m\] \[h=\frac{2\times 75\times {{10}^{-3}}}{(0.5\times {{10}^{-3}})(1000)10}\] \[\Rightarrow \] \[h=30\times {{10}^{-3}}\times 100\,cm\] \[=3\,cm\]You need to login to perform this action.
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