A) 4T
B) 2T
C) T
D) \[\frac{T}{2}\]
Correct Answer: B
Solution :
The time period of vibration magnetometer is given by \[T=2\pi \sqrt{\frac{I}{MH}}\] where\[I\]is moment of inertia, M the magnetic moment and H the horizontal component of earth's magnetic field. Also, \[I=m{{r}^{2}}\] where m is mass and r the radius. When mass is increased four times. \[I'=4I\] \[\therefore \] \[T'=2\pi \sqrt{\frac{4I}{MH}}\] \[=2\times 2\pi \sqrt{\frac{I}{MH}}=2T\]You need to login to perform this action.
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