A) 30%
B) 27.1%
C) 20%
D) 36%
Correct Answer: B
Solution :
Reduction in intensity after passing through first slab is\[=\frac{90}{100}\]of\[I=0.9I\] After second slab, intensity = 90% of (0.9\[I\]) = 81% of\[I\] = 0.81\[I\] After third slab, intensity = 90% of (0.81\[I\]) =72.9% of\[I\] \[\therefore \]Reduction in intensity = 27.1%You need to login to perform this action.
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