A) \[N{{O}_{2}}>NO_{2}^{+}>NO_{2}^{-}\]
B) \[NO_{2}^{-}>N{{O}_{2}}>NO_{2}^{+}\]
C) \[NO_{2}^{+}>N{{O}_{2}}>NO_{2}^{-}\]
D) \[NO_{2}^{+}>NO_{2}^{-}>N{{O}_{2}}\]
Correct Answer: C
Solution :
The decreasing order of bond angle is as: Species: \[NO_{2}^{+}\,\,\,>\,\,\,N{{O}_{2}}\,\,\,\,>\,\,NO_{2}^{-}\] Bond angle: \[180{}^\circ ~~~\,\,\,\,\,135{}^\circ ~~\,\,\,\,~115{}^\circ \]You need to login to perform this action.
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