A) 1
B) 4
C) 10
D) 13
Correct Answer: C
Solution :
\[pOH=p{{K}_{b}}+\log \frac{[Salt]}{[Base]}\] \[=5+\log \frac{0.01}{0.1}\] \[pOH=5-1\] \[pOH=4\] \[pH+pOH=14\] \[pH=14-pOH\] \[=14-4\] \[pH=10\]You need to login to perform this action.
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