A) increases
B) decreases
C) remains unchanged
D) becomes zero
Correct Answer: A
Solution :
The energy which is stored in the condenser is given by \[E=\frac{1}{2}.\frac{{{q}^{2}}}{C}\] ?.. (i) where q is charge and C the capacitance. Also, \[C=\frac{{{\varepsilon }_{0}}A}{d}\] ...(ii) From Eqs. (i) and (ii), we get \[E=\frac{1}{2}.\frac{{{q}^{2}}d}{{{\varepsilon }_{0}}A}\] \[\Rightarrow \] \[E\propto d\] When plate separation is increased energy increases.You need to login to perform this action.
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