A) 3.2 eV
B) 7 eV
C) 1.55 eV
D) 1 eV
Correct Answer: C
Solution :
From Planck's hypothesis, the energy of a photon, of frequency v is \[E=hv=\frac{hc}{\lambda }\] where c is speed of light and a. the wavelength. In the visible part, red colour has maximum wavelength \[\lambda =8000{\AA}\] \[\therefore \] \[E=\frac{6.6\times {{10}^{-34}}\times 3\times {{10}^{8}}}{8000\times {{10}^{-10}}}\] Also, \[1\text{ }eV=1.6\times {{10}^{-19}}J\] \[\therefore \] \[E=\frac{6.6\times {{10}^{-34}}\times 3\times {{10}^{8}}}{8000\times {{10}^{-10}}\times 1.6\times {{10}^{-19}}}\] \[=1.547eV\]
You need to login to perform this action.
You will be redirected in
3 sec
