A) 80 cm
B) 8 cm
C) 0.8 cm
D) 80 m
Correct Answer: B
Solution :
From the theorem of parallel axis, the moment of inertia I is equal to \[I={{I}_{CM}}+M{{a}^{2}}\] where\[{{I}_{CM}}\]where moment of inertia is about centre of mass and a the distance of axis from centre. \[\therefore \] \[I=M{{K}^{2}}+M\times {{(6)}^{2}}\] \[MK_{1}^{2}=M{{K}^{2}}+36M\] \[\Rightarrow \] \[K_{1}^{2}={{K}^{2}}+36\] \[\Rightarrow \] \[{{(10)}^{2}}={{K}^{2}}+36\] \[\Rightarrow \]\[{{K}^{2}}=100-36=64\] \[\Rightarrow \] \[K=8\text{ }cm\]
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