J & K CET Medical J & K - CET Medical Solved Paper-2004

  • question_answer
    The intensity of sound gets reduced by 10% on passing through a slab. The reduction in intensity on passage through three consecutive slabs is :

    A)  30%                                      

    B)  27.1%

    C)  20%                                      

    D)  36%

    Correct Answer: B

    Solution :

                    Reduction in intensity after passing through first slab is\[=\frac{90}{100}\]of\[I=0.9I\] After second slab, intensity = 90% of (0.9\[I\])       = 81% of\[I\]       = 0.81\[I\] After third slab, intensity = 90% of (0.81\[I\])   =72.9% of\[I\] \[\therefore \]Reduction in intensity = 27.1%


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