A) \[NaCl\]
B) \[KCl\]
C) \[BaC{{l}_{2}}\]
D) \[AlC{{l}_{3}}\]
Correct Answer: D
Solution :
According to Hardy Schuize rule, the coagulating power of an electrolyte is directly proportional to the valency of active ions. Hence, to coagulate negative sol of\[A{{s}_{2}}{{S}_{3}}\]the coagulating power of different cations decrease as: \[A{{l}^{3+}}>B{{a}^{2+}}>N{{a}^{+}}\]
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