A) First
B) Second
C) Third
D) Fourth
Correct Answer: C
Solution :
For an open pipe of length\[l,\]the frequency n is given by \[n=n.\frac{v}{2l}\] where v is velocity of sound,\[n\] the overtone. Given, \[n=480\text{ }Hz,\text{ }l=1\text{ }m;\] \[v=330\text{ }m/s\] \[n=\frac{n(2l)}{v}\] \[=\frac{480\times 2\times 1}{330}=2.9\approx 3\] Hence, this is the second overtone or third harmonic.You need to login to perform this action.
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