J & K CET Medical J & K - CET Medical Solved Paper-2005

  • question_answer
    The oxidation number of xenon in\[XeO{{F}_{2}}\]is:

    A)  zero                                     

    B)  2

    C)  4                                            

    D)  3

    Correct Answer: C

    Solution :

                    Let the oxidation number of\[Xe\]is\[x\]in\[XeO{{F}_{2}}\]. \[x+(-2)+2(-1)=0\] \[x-2-2=0\] \[x=+4\]


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