A) 5
B) 9
C) 4.5
D) 11
Correct Answer: B
Solution :
\[[O{{H}^{-}}]=1\times {{10}^{-5}}\] \[pOH=-log[O{{H}^{-}}]\] \[=-\log [1\times {{10}^{-5}}]\] \[pOH=5\] \[pH+pOH=14\] \[pH=14-pOH\] \[=14-5\] \[pH=9\]You need to login to perform this action.
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