A) monodentate ligand
B) bidentate ligand
C) tridentate ligand
D) polydentate ligand
Correct Answer: B
Solution :
Ethylenediamine is a bidentate ligand. \[\underset{\begin{smallmatrix} | \\ C{{H}_{2}}-\underset{\bullet \,\bullet }{\mathop{N}}\,{{H}_{2}} \end{smallmatrix}}{\mathop{C{{H}_{2}}-\overset{\bullet \,\bullet }{\mathop{N}}\,{{H}_{2}}}}\,\]
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