A) \[C{{O}_{2}}\]
B) \[B{{F}_{3}}\]
C) \[S{{F}_{4}}\]
D) \[N{{H}_{3}}\]
Correct Answer: D
Solution :
In\[N{{H}_{3}}\text{ s}{{p}^{3}}\]hybridisation is present but its shape is pyramidal due to the presence of one lone pair electrons.
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