A) Methane
B) Acetylene
C) 1-butene
D) Neo-pentane
Correct Answer: B
Solution :
In\[{{C}_{2}}{{H}_{2}}\]each C-atom is sp-hybridised which contains 50% 5-character. The greater the \[s-\]character of an orbital the bonding electron pair will be more inclined towards the nucleus as a result carbon would acquire a negative charge and hydrogen is a positive charge. Hence, it is acidic in nature. \[H-\underset{sp}{\mathop{C}}\,\equiv \underset{sp}{\mathop{C_{\bullet }^{\bullet }}}\,H\]and removal of hydrogen as proton takes place.
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