A) dichloro carbine
B) trichloro carbine
C) chlorine atoms
D) chlorine molecules
Correct Answer: A
Solution :
When phenol reacts with chloroform and \[NaOH\]to give o-hydroxy benzaldehyde or salicylaldehyde. In this reaction dichlorocarbene\[({}_{\bullet }^{\bullet }CC{{l}_{2}})\]electrophile is generated. This reaction is called as Reimer-Tiemann reaction. \[O{{H}^{-}}+CHC{{l}_{3}}\xrightarrow{{}}HOH+{}_{\bullet }^{\bullet }CC{{l}_{3}}\] \[{}_{\bullet }^{\bullet }CCl_{3}^{-}\xrightarrow{{}}C{{l}^{-}}+\underset{dichlorocarbene}{\mathop{{}_{\bullet }^{\bullet }CC{{l}_{2}}}}\,\]
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