A) 4 A
B) 6 A
C) 3 A
D) 5 A
Correct Answer: A
Solution :
From Kirchhoffs first law, in an electric circuit the algebraic sum of the currents meeting at any junction is zero, i.e., \[\Sigma i=0\] \[\therefore \]Taking inward direction of current as positive and outward as negative, we have \[1A-3A-2A+I=0\] \[\Rightarrow \] \[I=4A\]You need to login to perform this action.
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