A) \[CrO_{4}^{2-}\]
B) \[Cr(OH)_{3}^{-}\]
C) \[C{{r}_{2}}O_{7}^{2-}\]
D) \[Cr{{(OH)}_{2}}\]
Correct Answer: A
Solution :
\[Cr{{O}_{3}}\]dissolves in aqueous\[NaOH\]to give sodium chromate. \[Cr{{O}_{3}}+2NaOH\xrightarrow{{}}\underset{sodium\text{ }carbonate}{\mathop{N{{a}_{2}}Cr{{O}_{4}}}}\,+{{H}_{2}}O\]You need to login to perform this action.
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