A) ethyl alcohol
B) ethyl bromide
C) bromobenzene
D) chlorobenzene
Correct Answer: B
Solution :
Ethyl bromide reacts with KCN to give ethyl cyanide. \[\underset{ethyl\text{ }bromide}{\mathop{{{C}_{2}}{{H}_{5}}Br}}\,+KCN(alc.)\xrightarrow{{}}\underset{ethyl\text{ }cyanide}{\mathop{{{C}_{2}}{{H}_{5}}CN}}\,\]\[+KBr\]You need to login to perform this action.
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