A) A and C are isobars
B) A and C are isotopes
C) A and B are isobars
D) A and B are isotopes
Correct Answer: B
Solution :
Let\[x\]be the mass number of A and Y the atomic number. Then, since atomic number and mass number remain conserved, we have \[_{y}{{A}^{x}}{{\xrightarrow[{}]{{}}}_{y-2}}{{B}^{x-4}}{{+}_{2}}H{{e}^{4}}\] \[_{y-2}{{B}^{x-4}}{{\xrightarrow[{}]{{}}}_{y}}{{B}^{x-4}}+{{2}_{-1}}{{e}^{0}}\] Hence, we observe that A and C are isotopes as their atomic numbers are same but mass numbers are different.
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